A mass of 2 kg is supported by a copper wire of length 4 m and diameter 4 mm. A cylindrical aluminum pillar 7 high has a radius of 30 cm. 5 m (L) long, how much compression (∆L) can the bone withstand before breaking. Assuming a human adult thigh bone (femur) is about. Under compression, it can withstand a stress of about 160 x 10 6 N/m 2 (stress) before breaking. Human bone has a Young’s Modulus of 14 x10 8 N/m 2 (Y). If the mass were removed, how far above the tabletop will be the bottom of the spring? Data Equation Math Answer k = 15 N/m hf = 0 m m = 0 kg hi = hf + x x = F ÷ k F = mg F = 0 (9) = 3 N x = 3.92/15 = 0 m hi = 0 + 0. A spring with a k = 15 N/m hangs 3 cm above a tabletop when a 400 g mass is hung from it. What is the k for the spring? Data Equation Math Answer m = 0 kg hi = 0 m hf = 0 m k = F÷ x x = |hf - hi| F = mg x = 0 – 0 = 0. A 250 g mass is hung from a spring that stretches from 93 cm to 62 cm. If the weight is removed, how far above the tabletop will the spring hang? Data Equation Math Answer k = 24 N/m hf = 0 m F = 12 N hi = hf + x x = F ÷ k x = 12 ÷ 24 = 0. The bottom of a spring with a k = 24 N/m is 0 m above a tabletop when 12 N are attached. How high above the table will the bottom of the spring be if 6 N are applied to the spring? Data Equation Math Answer k = 28 hi = 0 m F = 6 N hf = |hi - x| x = F ÷ k x = 6 ÷ 28 = 0. A spring has a k = 28 hangs at 85 cm above the tabletop. What is the force needed to stretch a spring, with a k = 13 N/m a total of 0 m? Data Equation Math Answer k = 13 N/m x = 0 m F = kx F = 13 (0) 2 N 4. What is the modulus for the spring? Data Equation Math Answer hi =0 m F = 4 N hf = 0 k = F ÷ x x= |hf – hi| x = |0 – 0| = 0. When 4 N are attached, it reaches to 54 cm. What is the modulus for the spring? Data Equation Math Answer x = 0 m F = 2 N k = F ÷ x K = 2 ÷ 0 17 N/m 2. A spring is stretched 0 m when a 2 N weight is hung from it. PHYSICS WORKSHEET STRESS, STRAIN, TENSION, COMPRESSION &ELASTICITY KEY & SOLUTIONS 2 2 Force of elasticity = Strain Area change in dimension = Degree of Deformation = orginal dimension in Pa (unit of Pressure) 1 Pa = 1 N/m Area = r = Stress F kx Modulus Stress Strain Measured π = 2 Stress Force Maximum Stress = Strain Minimum Area D ( ) **** You NEED THIS FOR 2 problems 2 Strain F L Y A L F A F L Y L A L L F Shear Stress A F h S Shear x A x h π Textbook content produced by OpenStax is licensed under a Creative Commons Attribution License. We recommend using aĪuthors: Paul Peter Urone, Roger Hinrichs Use the information below to generate a citation. Then you must include on every digital page view the following attribution: If you are redistributing all or part of this book in a digital format, Then you must include on every physical page the following attribution: If you are redistributing all or part of this book in a print format, Want to cite, share, or modify this book? This book uses the
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